MATH SOLVE

4 months ago

Q:
# Find the equation of the line that passes through (-1,2) and is perpendicular to 2y = x β 3. Leave your answer in the form y = mx + c

Accepted Solution

A:

Answer:y = - 2xStep-by-step explanation:The equation of a line in slope- intercept form isy = mx + c ( m is the slope and c the y- intercept )Rearrange2y = x - 3 into this formDivide all terms by 2 y = [tex]\frac{1}{2}[/tex] x - [tex]\frac{3}{2}[/tex] β in slope- intercept formwith slope m = [tex]\frac{1}{2}[/tex]Given a line with slope m then the slope of a line perpendicular to it is[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{\frac{1}{2} }[/tex] = - 2, hencey = - 2x + c β is the partial equation of the perpendicular lineTo find c substitute (- 1, 2) into the partial equation2 = 2 + c β c = 2 - 2 = 0y = - 2x β equation of perpendicular line