Write an equation of the line that is perpendicular to -x + y = 5 and passes through the point (2, -5).
Accepted Solution
A:
Convert to y = mx + by = x + 5The slope is oneNow, convert this into point slope form:y - y1 = m(x - x1)y + 5 = 1 (x - 2)y + 5 = x - 2Subtract 5 from both sides.y = x - 7An equation of the line that is perpendicular to -x + y = 5 and passes through the point (2, -5) should be y = x - 7